Java: Generator of true's & false's combinations by giving the number N;

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野的像风
野的像风 2020-12-09 13:53

I tied to simplify the task as much as possible, so I could apply it to my algorithm.

And here is the challenge for mathematicians and programmers:

I need to

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  •  孤城傲影
    2020-12-09 14:17

    Just a clue but think about the bits that are set for a number with at most 'n' bits. You'll see if you go from 0 to 'n' number of bits (3 in this case); the bits are 000, 001, 010, 011, 100, 101, 110, 111. You can figure out the max number that can fit in 'n' bits by using the ((n*n)-1) formula.

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