what's the mechanism of sizeof() in C/C++?

Question

It seems sizeof is not a real function?

for example, if you write like this:

int i=0;
printf(\"%d\\n\", sizeof(++i));
printf(\"%d\\n\", i);
         


        

Answer 1

Exactly what it's meant to do: puts directly the constant "the size of the variable/constant/type/etc" into the code