How to response ajax request in Django

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悲哀的现实
悲哀的现实 2020-12-09 12:48

I have code like this:

$(document).ready(function(){
    $(\'#error\').hide();
    $(\'#submit\').click(function(){
        var name = $(\"#name\").val();
           


        
6条回答
  •  被撕碎了的回忆
    2020-12-09 13:39

    how about create dict and parse to json:

    name = request.POST.get('name')
    dict = {'name':name}
    return HttpResponse(json.dumps(dict), content_type='application/json')
    

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