How to get self into a Python method without explicitly accepting it

Question

I\'m developing a documentation testing framework -- basically unit tests for PDFs. Tests are (decorated) methods of instances of classes defined by the framework, and these

Answer 1

little upgrade for aaronasterling's solution( i haven't enough reputation to comment it ):

def wrap(f):
    @functools.wraps(f)
    def wrapper(self,*arg,**kw):
        f.func_globals['self'] = self        
        return f(*arg,**kw)
    return wrapper

but both this solutions will work unpredictable if f function will be called recursively for different instance, so you have to clone it like this:

import types
class wrap(object):
    def __init__(self,func):
        self.func = func
    def __get__(self,obj,type):
        new_globals = self.func.func_globals.copy()
        new_globals['self'] = obj
        return types.FunctionType(self.func.func_code,new_globals)
class C(object):
    def __init__(self,word):
        self.greeting = word
    @wrap
    def greet(name):
        print(self.greeting+' , ' + name+ '!')
C('Hello').greet('kindall')