How to extract substring in parentheses using Regex pattern

Question

This is probably a simple problem, but unfortunately I wasn\'t able to get the results I wanted...

Say, I have the following line:

\"Wouldn\'t It B         


        

Answer 1

Edit: After examining your document, the problem is that there are non-breaking spaces before the parentheses, not regular spaces. So this regex should work: ""[ \xA0]*\(([^)]+)\)

""       'quote (twice to escape)
[ \xA0]* 'zero or more non-breaking (\xA0) or a regular spaces
\(       'left parenthesis
(        'open capturing group
[^)]+    'anything not a right parenthesis
)        'close capturing group
\)       'right parenthesis

In a function:

Public Function GetStringInParens(search_str As String)
Dim regEx As New VBScript_RegExp_55.RegExp
Dim matches
    GetStringInParens = ""
    regEx.Pattern = """[ \xA0]*\(([^)]+)\)"
    regEx.Global = True
    If regEx.test(search_str) Then
        Set matches = regEx.Execute(search_str)
        GetStringInParens = matches(0).SubMatches(0)
    End If
End Function