PHP: date “Yesterday”, “Today”

Question

I have a little function that shows latest activity, it grab timestamp in unix format from the db, and then it echo out with this line:

 date(\"G:i:s j M -Y\         


        

Answer 1

You have to compare day with day, secondes comparaison are totally wrong :

If we are today morning, that means yesterday night is today (by minus 24h) ^^

Here a method I use for Kinoulink ( a french startup ) :

public function formatDateAgo($value)
{
    $time = strtotime($value);
    $d = new \DateTime($value);

    $weekDays = ['Lundi', 'Mardi', 'Mercredi', 'Jeudi', 'Vendredi', 'Samedi', 'Dimanche'];
    $months = ['Janvier', 'Février', 'Mars', 'Avril',' Mai', 'Juin', 'Juillet', 'Aout', 'Septembre', 'Octobre', 'Novembre', 'Décembre'];

    if ($time > strtotime('-2 minutes'))
    {
        return 'Il y a quelques secondes';
    }
    elseif ($time > strtotime('-30 minutes'))
    {
        return 'Il y a ' . floor((strtotime('now') - $time)/60) . ' min';
    }
    elseif ($time > strtotime('today'))
    {
        return $d->format('G:i');
    }
    elseif ($time > strtotime('yesterday'))
    {
        return 'Hier, ' . $d->format('G:i');
    }
    elseif ($time > strtotime('this week'))
    {
        return $weekDays[$d->format('N') - 1] . ', ' . $d->format('G:i');
    }
    else
    {
        return $d->format('j') . ' ' . $months[$d->format('n') - 1] . ', ' . $d->format('G:i');
    }
}