Convert R list to dataframe with missing/NULL elements

Question

Given a list:

alist = list(
  list(name=\"Foo\",age=22),
  list(name=\"Bar\"),
  list(name=\"Baz\",age=NULL)
 )

what\'s the best way to con

Answer 1

A comment mentioned wanting only a single loop, which can be achieved with @flodel's answer just by putting the body of the two loops together:

rbind.fill(lapply(alist, function(f) {
  as.data.frame(Filter(Negate(is.null), f))
}))

giving

  name age
1  Foo  22
2  Bar  NA
3  Baz  NA