Why does calloc require two parameters and malloc just one?

Question

It\'s very bothersome for me to write calloc(1, sizeof(MyStruct)) all the time. I don\'t want to use an idea like wrapping this method and etc. I mean I want to

Answer 1

it is just by design.

you could write your own calloc

void *mycalloc(size_t num, size_t size)
{
    void *block = malloc(num * size);
    if(block != NULL)
        memset(block, 0, num * size);
    return block;
}