Get called function name as string

Question

I\'d like to display the name of a function I\'m calling. Here is my code

void (*tabFtPtr [nbExo])(); // Array of function pointers
int i;
for (i = 0; i <         


        

Answer 1

I'm not sure this is what you want, but you could do something like this. Declare a structure to hold a function name and address, and an array of functions at file scope:

#define FNUM 3

struct fnc {
    void *addr;
    char name[32];
};

void (*f[FNUM])();
struct fnc fnames[FNUM];

Initialise these in your code manually by function name, e.g.

    fnames[0] = (struct fnc){foo1, "foo1"}; // function address + its name
    fnames[1] = (struct fnc){foo2, "foo2"};
    fnames[2] = (struct fnc){foo3, "foo3"};

Make a function to search the array, e.g.

char *getfname(void *p)
{
        for (int i = 0; i < FNUM; i++) {
                if (fnames[i].addr == p)
                        return fnames[i].name;
        }
        return NULL;
}

I ran a quick test of this. I initialised the array in main, and called foo1(). Here's my function, and the output:

void foo1(void)
{
    printf("The pointer of the current function is %p\n", getfnp(__func__));
    printf("The name of this function is %s\n", getfname(getfnp(__func__)));
    printf("The name of the function at pointer f[2] (%p) is '%s'\n", f[2],
        getfname(f[2]));    
}

The pointer of the current function is 0x400715
The name of this function is foo1
The name of the function at pointer f[2] (0x40078c) is 'foo3'

Or, more generally:

void foo2(void)
{
    for (int i = 0; i < FNUM; i++) {
        printf("Function f[%d] is called '%s'\n", i, getfname(f[i]));
    }
}

Function f[0] is called 'foo1'
Function f[1] is called 'foo2'
Function f[2] is called 'foo3'