Each GROUP BY expression must contain at least one column that is not an outer reference

Question

What am I doing wrong here? I am getting this error on:

SELECT LEFT(SUBSTRING(batchinfo.datapath, PATINDEX(\'%[0-9][0-9][0-9]%\', batchinfo.datapath), 8000),         


        

Answer 1

You can't group by literals, only columns.

You are probably looking for something like this:

select 
LEFT(SUBSTRING(batchinfo.datapath, PATINDEX('%[0-9][0-9][0-9]%', batchinfo.datapath), 8000), PATINDEX('%[^0-9]%', SUBSTRING(batchinfo.datapath, PATINDEX('%[0-9][0-9][0-9]%', batchinfo.datapath), 8000))-1) as pathinfo,
qvalues.name,
qvalues.compound,
qvalues.rid
 from batchinfo join qvalues on batchinfo.rowid=qvalues.rowid
where LEN(datapath)>4
group by pathinfo, qvalues.name, qvalues.compound
having rid!=MAX(rid)

First of all, you have to give that first expression a column name with as. Then you have to specify the names of the columns in the group by expression.