Check if a string exists in an array case insensitively

Question

Declaration:

let listArray = [\"kashif\"]
let word = \"kashif\"

then this

contains(listArray, word) 

Ret

Answer 1

SWIFT 3.0:

Finding a case insensitive string in a string array is cool and all, but if you don't have an index it can not be cool for certain situations.

Here is my solution:

let stringArray = ["FOO", "bar"]()
if let index = stringArray.index(where: {$0.caseInsensitiveCompare("foo") == .orderedSame}) {
   print("STRING \(stringArray[index]) FOUND AT INDEX \(index)")
   //prints "STRING FOO FOUND AT INDEX 0"                                             
}

This is better than the other answers b/c you have index of the object in the array, so you can grab the object and do whatever you please :)