Get documents with tags in list, ordered by total number of matches

Question

Given the following MongoDB collection of documents :

{
 title : \'shirt one\'
 tags : [
  \'shirt\',
  \'cotton\',
  \'t-shirt\',
  \'black\'
 ]
},
{
 title         


        

Answer 1

As i answered in In MongoDB search in an array and sort by number of matches

It's possible using Aggregation Framework.

Assumptions

• tags attribute is a set (no repeated elements)

Query

This approach forces you to unwind the results and reevaluate the match predicate with unwinded results, so its really inefficient.

db.test_col.aggregate(
    {$match: {tags: {$in: ["shirt","cotton","black"]}}}, 
    {$unwind: "$tags"}, 
    {$match: {tags: {$in: ["shirt","cotton","black"]}}},
    {$group: {
        _id:{"_id":1}, 
        matches:{$sum:1}
    }}, 
    {$sort:{matches:-1}}
);

Expected Results

{
    "result" : [
        {
            "_id" : {
                "_id" : ObjectId("5051f1786a64bd2c54918b26")
            },
            "matches" : 3
        },
        {
            "_id" : {
                "_id" : ObjectId("5051f1726a64bd2c54918b24")
            },
            "matches" : 2
        },
        {
            "_id" : {
                "_id" : ObjectId("5051f1756a64bd2c54918b25")
            },
            "matches" : 1
        }
    ],
    "ok" : 1
}