Given a line with first end point P(x1,y1) another end point is unknown, intersect with a circle that located at origin with radius R at only one point(tangent) T(x2,y2). An
imbrizi's answer assumes that the circle's center is (0,0).
This is the correct answer in Objective C:
- (NSArray *)pointsTangentToCircleWithCenter:(CGPoint)centerPoint
radius:(CGFloat)radius
outerPoint:(CGPoint)outerPoint {
float dx = centerPoint.x - outerPoint.x;
float dy = centerPoint.y - outerPoint.y;
float dd = sqrt(dx*dx + dy*dy);
float a = asinf(radius / dd);
float b = atan2f(dy, dx);
float t1 = b - a;
CGPoint tangentPoint1 = CGPointMake(centerPoint.x + radius*sinf(t1),
centerPoint.y + radius*-cosf(t1));
float t2 = b + a;
CGPoint tangentPoint2 = CGPointMake(centerPoint.x + radius*-sinf(t2),
centerPoint.y + radius*cosf(t2));
NSArray *points = @[
[NSValue valueWithCGPoint:tangentPoint1],
[NSValue valueWithCGPoint:tangentPoint2]
];
return points;
}