In C++ how is function overloading typically implemented?

Question

If there is no function overloading, the function name serves as the address of the function code, and when a function is being called, its address is easy to find using its

Answer 1

It is, I believe, achieved through name mangling:

the functions you know as foo(int) and foo(double) are actually named something like int_foo() and double_foo() (or similar, I'm not entirely sure of the particular semantics employed for C++). This means that C++ symbols are usually an order of magnitude larger than the names they are given in code.