How can I read a single line from stdin?

Question

I\'m asking for the equivalent of fgets() in C.

let line = ...;
println!(\"You entered: {}\", line);

I\'ve read How to read us

Answer 1

Read a single line from stdin:

    let mut line = String::new();
    std::io::stdin().read_line(&mut line)?; // including '\n'

You may remove '\n' using line.trim_end()

Read until EOF:

    let mut buffer = String::new();
    std::io::stdin().read_to_string(&mut buffer)?;

---

Using implicit synchronization:

use std::io;
fn main() -> io::Result<()> {
    let mut line = String::new();
    io::stdin().read_line(&mut line)?;

    println!("You entered: {}", line);
    Ok(())
}

---

Using explicit synchronization:

use std::io::{self, BufRead};

fn main() -> io::Result<()> {
    let stdin = io::stdin();
    let mut handle = stdin.lock();

    let mut line = String::new();
    handle.read_line(&mut line)?;

    println!("You entered: {}", line);
    Ok(())
}

---

If you interested in the number of bytes e.g. n, use:
let n = handle.read_line(&mut line)?;
or
let n = io::stdin().read_line(&mut line)?;

Try this:

use std::io;
fn main() -> io::Result<()> {
    let mut line = String::new();
    let n = io::stdin().read_line(&mut line)?;

    println!("{} bytes read", n);
    println!("You entered: {}", line);
    Ok(())
}

See doc