Checking if particular value (in cell) is NaN in pandas DataFrame not working using ix or iloc

Question

Lets say I have following pandas DataFrame:

import pandas as pd
df = pd.DataFrame({\"A\":[1,pd.np.nan,2], \"B\":[5,6,0]})
         


        

Answer 1

The above answer is excellent. Here is the same with an example for better understanding.

>>> import pandas as pd
>>>
>>> import numpy as np
>>>
>>> pd.Series([np.nan, 34, 56])
0     NaN
1    34.0
2    56.0
dtype: float64
>>>
>>> s = pd.Series([np.nan, 34, 56])
>>> pd.isnull(s[0])
True
>>>

I also tried couple of times, the following trials did not work. Thanks to @MaxU.

>>> s[0]
nan
>>>
>>> s[0] == np.nan
False
>>>
>>> s[0] is np.nan
False
>>>
>>> s[0] == 'nan'
False
>>>
>>> s[0] == pd.np.nan
False
>>>