c# ProcessStartInfo.Start - reading output but with a timeout

Question

If you want to start another process and wait (with time out) to finish you can use the following (from MSDN).

//Set a time-out value.
int timeOut=5000;
//Ge         


        

Answer 1

You could also use the APM, like this:

Define a delegate for the ReadToEnd call:

private delegate string ReadToEndDelegate();

Then use the delegate to call the method like this:

ReadToEndDelegate asyncCall = reader.ReadToEnd;
IAsyncResult asyncResult = asyncCall.BeginInvoke(null, null);
asyncResult.AsyncWaitHandle.WaitOne(TimeSpan.FromSeconds(10));
asyncCall.EndInvoke(asyncResult);

EDIT: Error handling removed for clarity.