There are two unsigned ints (x and y) that need to be subtracted. x is always larger than y. However, both x and y can wrap around; for example, if they were both bytes, af
The problem should be stated as follows:
Let's assume the position (angle) of two pointers a and b of a clock is given by an uint8_t. The whole circumerence is devided into the 256 values of an uint8_t. How can the smaller distance between the two pointer be calculated efficiently?
A solution is:
uint8_t smaller_distance = abs( (int8_t)( a - b ) );
I suspect there is nothing more effient as otherwise there would be something more efficient than abs().