python regex: get end digits from a string

Question

I am quite new to python and regex (regex newbie here), and I have the following simple string:

s=r\"\"\"99-my-name-is-John-Smith-6376827-%^-1-2-767980716\"\         


        

Answer 1

You can use re.match to find only the characters:

>>> import re
>>> s=r"""99-my-name-is-John-Smith-6376827-%^-1-2-767980716"""
>>> re.match('.*?([0-9]+)$', s).group(1)
'767980716'

Alternatively, re.finditer works just as well:

>>> next(re.finditer(r'\d+$', s)).group(0)
'767980716'

Explanation of all regexp components:

• .*? is a non-greedy match and consumes only as much as possible (a greedy match would consume everything except for the last digit).
• [0-9] and \d are two different ways of capturing digits. Note that the latter also matches digits in other writing schemes, like ୪ or ൨.
• Parentheses (()) make the content of the expression a group, which can be retrieved with group(1) (or 2 for the second group, 0 for the whole match).
• + means multiple entries (at least one number at the end).
• $ matches only the end of the input.