“synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.” problem in TensorFlow

Question

I installed TensorFlow 1.10.1 but when I tried to import TensorFlow it said that I need TensorFlow version 1.10.0. Thus, I installed it and now I get the following warnings:

Answer 1

I had the same problem in my linux laptop with tensorflow in python3 v3.6

Actually, you just need to change some lines in 2 files :

• 1

  ~/.local/lib/python3.6/site-packages/tensorflow/python/framework/dtypes.py

in your case :

C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py

now change this code : (line 516)

_np_qint8 = np.dtype([("qint8", np.int8, 1)])
_np_quint8 = np.dtype([("quint8", np.uint8, 1)])
_np_qint16 = np.dtype([("qint16", np.int16, 1)])
_np_quint16 = np.dtype([("quint16", np.uint16, 1)])
_np_qint32 = np.dtype([("qint32", np.int32, 1)])


# _np_bfloat16 is defined by a module import.

# Custom struct dtype for directly-fed ResourceHandles of supported type(s).
np_resource = np.dtype([("resource", np.ubyte, 1)])

by this code :

_np_qint8 = np.dtype([("qint8", np.int8, (1,))])
_np_quint8 = np.dtype([("quint8", np.uint8, (1,))])
_np_qint16 = np.dtype([("qint16", np.int16, (1,))])
_np_quint16 = np.dtype([("quint16", np.uint16, (1,))])
_np_qint32 = np.dtype([("qint32", np.int32, (1,))])

# _np_bfloat16 is defined by a module import.

# Custom struct dtype for directly-fed ResourceHandles of supported type(s).
np_resource = np.dtype([("resource", np.ubyte, (1,))])

you have to do the same on this file :

• 2

  ~/.local/lib/python3.6/site-packages/tensorboard/compat/tensorflow_stub/dtypes.py

in your case :

C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard/compat/tensorflow_stub/dtypes.py

and it will work.