C# Difference between First() and Find()

Question

So I know that Find() is only a List method, whereas First() is an extension for any IEnumerable. I als

Answer 1

BTW Find is rather equal to FirstOrDefault() than to First(). Because if predicate of First() is not satisfied with any list elements you will get an exception. Here what returns a dotpeek, another great free reflector replacement with some of ReSharper features

Here for Enumerable.First(...) and Enumerable.FirstOrDefault(...) extension methods:

    public static TSource FirstOrDefault(this IEnumerable source, Func predicate) {
        if (source == null) throw Error.ArgumentNull("source");
        if (predicate == null) throw Error.ArgumentNull("predicate");
        foreach (TSource element in source) { 
            if (predicate(element)) return element;
        } 
        return default(TSource); 
    }


    public static TSource First(this IEnumerable source, Func predicate) {
        if (source == null) throw Error.ArgumentNull("source"); 
        if (predicate == null) throw Error.ArgumentNull("predicate"); 
        foreach (TSource element in source) {
            if (predicate(element)) return element; 
        }
        throw Error.NoMatch();
    }

and here is for List<>.Find:

/// 

/// Searches for an element that matches the conditions defined by the specified predicate, and returns the first occurrence within the entire .
/// 
/// 
/// 
/// The first element that matches the conditions defined by the specified predicate, if found; otherwise, the default value for type .
/// 
/// The  delegate that defines the conditions of the element to search for. is null.
[__DynamicallyInvokable]
public T Find(Predicate match)
{
  if (match == null)
    ThrowHelper.ThrowArgumentNullException(ExceptionArgument.match);
  for (int index = 0; index < this._size; ++index)
  {
    if (match(this._items[index]))
      return this._items[index];
  }
  return default (T);
}