How do I specify an integer literal of type unsigned char in C++?

Question

I can specify an integer literal of type unsigned long as follows:

const unsigned long example = 9UL;

How do I do likewise for an unsigned

Answer 1

There is no suffix for unsigned char types. Integer constants are either int or long (signed or unsigned) and in C99 long long. You can use the plain 'U' suffix without worry as long as the value is within the valid range of unsigned chars.