How to use Promise.all() with Typescript

Question

Here is what I want to do:

Promise.all([aurelia.start(), entityManagerProvider.initialize()])
    .then((results:Array) => {
        let aureli         


        

Answer 1

At least from TypeScript 2.7.1 onwards, the compiler seems to resolve the types without help, with a syntax like this:

Promise.all([fooPromise, barPromise]).then(([foo, bar]) => {
  // compiler correctly warns if someField not found from foo's type
  console.log(foo.someField);
});

Hat tip: @JamieBirch (from comment to @AndrewKirkegaard's answer)