How to create and send the json data to server using swift language

Question

I\'m new to IOS development and I have started with the swift language.

I\'m trying to get the value from two text fields and convert those two text fields into json

Answer 1

By using http POST method with NSURLSession. Let's say you are calling submitAction method on the press of the login button

Swift 3

@IBAction func submitAction(_ sender: UIButton) {

    //declare parameter as a dictionary which contains string as key and value combination. considering inputs are valid

    let parameters: [String: String] = ["name": nametextField.text, "password": passwordTextField.text]

    //create the url with URL
    let url = URL(string: "http://myServerName.com/api")! //change the url

    //create the session object
    let session = URLSession.shared

    //now create the URLRequest object using the url object
    var request = URLRequest(url: url)
    request.httpMethod = "POST" //set http method as POST

    do {
        request.httpBody = try JSONSerialization.data(withJSONObject: parameters, options: .prettyPrinted) // pass dictionary to nsdata object and set it as request body

    } catch let error {
        print(error.localizedDescription)
    }

    request.addValue("application/json", forHTTPHeaderField: "Content-Type")
    request.addValue("application/json", forHTTPHeaderField: "Accept")

    //create dataTask using the session object to send data to the server
    let task = session.dataTask(with: request, completionHandler: { data, response, error in

        guard error == nil else {
            return
        }

        guard let data = data else {
            return
        }

        do {
            //create json object from data
            if let json = try JSONSerialization.jsonObject(with: data, options: .mutableContainers) as? [String: Any] {
                print(json)
                // handle json...
            }

        } catch let error {
            print(error.localizedDescription)
        }
    })
    task.resume()
}