nodejs equivalent of this .htaccess

Question

Is it possible to build a code like this in node.js?

     RewriteEngine on

     RewriteCond% {REQUEST_URI}! / (V         


        

Answer 1

The final structure is:

var express = require('express'), url = require('url');

var app = express();
app.use(function(req, res, next) {
    console.log('%s %s', req.method, req.url);
    next();
});
app.configure(function() {
    var pub_dir = __dirname + '/public';
    app.set('port', process.env.PORT || 8080);
    app.engine('.html', require('ejs').__express);
    app.set('views', __dirname + '/views');
    app.set('view engine', 'html');
    app.use(express.bodyParser());
    app.use(express.methodOverride());
    app.use(express.cookieParser());
    app.use(express.static(pub_dir));
    app.use(app.router);
});
app.get('/*', function(req, res) {
    if (req.xhr) {
        var pathname = url.parse(req.url).pathname;
        res.sendfile('index.html', {root: __dirname + '/public' + pathname});
    } else {
        res.render('index');
    }
});

app.listen(app.get('port'));

Thanks everyone. PD: Render html with module ejs