How to fill specific positional arguments with partial in python?

Question

Basically, what I\'d like to do is:

>>> from functools import partial
>>> partial(str.startswith, prefix=\'a\')(\'a\')
Traceback (most rece         


        

Answer 1

If you really need this you can use rpartial from funcy 3rd-party library.

Its code is here:

def rpartial(func, *args):
    return lambda *a: func(*(a + args))

So, your case can be handled as following:

>>> startswith_a = rpartial(str.startswith, 'a')
>>> startswith_a('abc')
True
>>> startswith_a('def')
False