This compiles without any warnings.
Is this legal in C and C++ or does it just work in gcc and clang?
If it is legal, is it some new thing after C99?
C11, 6.8.6.4 "The return statement":
A
returnstatement with an expression shall not appear in a function whose return type isvoid.
No, you may not use an expression, even if it is of void type.
From the foreword of the same document:
Major changes in the second edition included:
[...]
returnwithout expression not permitted in function that returns a value (and vice versa)
So this was a change from C89 -> C99 (the second edition of the language standard), and has been that way ever since.
C++14, 6.6.3 "The return statement":
A return statement with an expression of non-void type can be used only in functions returning a value [...] A return statement with an expression of type void can be used only in functions with a return type of cv void; the expression is evaluated just before the function returns to its caller.
Yes, you may use an expression if it is of void type (that's been valid since C++98).