Java 8 lambda get and remove element from list

Question

Given a list of elements, I want to get the element with a given property and remove it from the list. The best solution I found is:

Produce         


        

Answer 1

Combining my initial idea and your answers I reached what seems to be the solution to my own question:

public ProducerDTO findAndRemove(String pod) {
    ProducerDTO p = null;
    try {
        p = IntStream.range(0, producersProcedureActive.size())
             .filter(i -> producersProcedureActive.get(i).getPod().equals(pod))
             .boxed()
             .findFirst()
             .map(i -> producersProcedureActive.remove((int)i))
             .get();
        logger.debug(p);
    } catch (NoSuchElementException e) {
        logger.error("No producer found with POD [" + pod + "]");
    }
    return p;
}

It lets remove the object using remove(int) that do not traverse again the list (as suggested by @Tunaki) and it lets return the removed object to the function caller.

I read your answers that suggest me to choose safe methods like ifPresent instead of get but I do not find a way to use them in this scenario.

Are there any important drawback in this kind of solution?

Edit following @Holger advice

This should be the function I needed

public ProducerDTO findAndRemove(String pod) {
    return IntStream.range(0, producersProcedureActive.size())
            .filter(i -> producersProcedureActive.get(i).getPod().equals(pod))      
            .boxed()                                                                
            .findFirst()
            .map(i -> producersProcedureActive.remove((int)i))
            .orElseGet(() -> {
                logger.error("No producer found with POD [" + pod + "]"); 
                return null; 
            });
}