Reversing a linked list in python

Question

I am asked to reverse a which takes head as parameter where as head is a linked list e.g.: 1 -> 2 -> 3 which was returned from a function already defined I tried to implemen

Answer 1

U can use mod function to get the remainder for each iteration and obviously it will help reversing the list . I think you are a student from Mission R and D

head=None   
prev=None
for i in range(len):
    node=Node(number%10)
    if not head:
        head=node
    else:
        prev.next=node
    prev=node
    number=number/10
return head