TCP standard has \"simultaneous open\" feature.
The implication of the feature, client trying to connect to local port, when the port is from ephemeral range, can o
In my opinion, this is a bug in the TCP spec; listening sockets shouldn't be able to send unsolicited SYNs, and receiving a SYN (rather than a SYN+ACK) after you've sent one should be illegal and result in a reset, which would quickly let the client close the unluckily-chosen local port. But nobody asked for my opinion ;)
As you say, the obvious answer is not to listen in the ephemeral port range. Another solution, if you know you'll be connecting to a local machine, is to design your protocol so that the server sends the first message, and have a short timeout on the client side for receiving that message.