I have a quick question about serving files in Go. There is the great timesaving FileServer handler, but for my use case, I only have 2 or 3 files (js and css) that go with
I would store the files in variable as plain text. Something like this:
package main
import (
"fmt"
"log"
"net/http"
)
var files = map[string]string{}
func init() {
files["style.css"] = `
/* css file content */
body { background-color: pink; }
`
}
func init() {
files["index.html"] = `
Hello world!
`
}
func main() {
for fileName, content := range files {
contentCpy := content
http.HandleFunc("/"+fileName, func(w http.ResponseWriter, r *http.Request) {
fmt.Fprintf(w, "%s\n", contentCpy)
})
}
log.Fatal(http.ListenAndServe(":8080", nil))
}
That way, it is pretty easy to have your makefile or build script so something like:
for file in index.html style.css; do echo "package main\nfunc init() { files[\"$file\"] = \`$(cat $file)\` }" | gofmt -s > $file.go; done; go build && ./httptest