How do I get the path of the current executed file in Python?

Question

This may seem like a newbie question, but it is not. Some common approaches don\'t work in all cases:

sys.argv[0]

This means using path = os.path.abs

Answer 1

First, you need to import from inspect and os

from inspect import getsourcefile
from os.path import abspath

Next, wherever you want to find the source file from you just use

abspath(getsourcefile(lambda:0))