I\'ve taken a look to urlparse.urlparse
method documentation and I\'m a little bit confused about what is the parameters
part (not to be confused w
Wow... I was not aware of that, see example:
>>> urlparse.urlparse("http://some.page.pl/nothing.py;someparam=some;otherparam=other?query1=val1&query2=val2#frag")
ParseResult(scheme='http', netloc='some.page.pl', path='/nothing.py', params='someparam=some;otherparam=other', query='query1=val1&query2=val2', fragment='frag')
And help(urlparse.urlparse):
Help on function urlparse in module urlparse:
urlparse(url, scheme='', allow_fragments=True)
Parse a URL into 6 components:
:///;?#
Return a 6-tuple: (scheme, netloc, path, params, query, fragment).
Note that we don't break the components up in smaller bits
(e.g. netloc is a single string) and we don't expand % escapes.