How can I get argv[] as int?

Question

i have a piece of code like this:

int main (int argc, char *argv[]) 
{
   printf(\"%d\\t\",(int)argv[1]);
   printf(\"%s\\t\",(int)argv[1]);
}

Answer 1

You can use strtol for that:

long x;
if (argc < 2)
    /* handle error */

x = strtol(argv[1], NULL, 10);

Alternatively, if you're using C99 or better you could explore strtoimax.