Print template typename at compile time

Question

When creating a template function in C++ is there a simple way to have the typename of the template represented as a string? I have a simple test case to show what I\'m try

Answer 1

Since you have said you would need this for debugging purpose, maybe a runtime solution is also acceptable. And you have tagged this as g++ so you don't want to be standard conform.

Here is what that means:

#include  // the libstdc++ used by g++ does contain this header

template 
void print(const type *addr) // you wanted a pointer
{
  char * name = abi::__cxa_demangle(typeid(*addr).name(), 0, 0, NULL);
  printf("type is: %s\n", name);
  delete name;
}

print(new unsigned long);    // prints "type is: unsigned long"
print(new std::vector); // prints "type is: std::vector >"

EDIT: corrected the memory leak. Thx to Jesse.