Splitting an array into equal parts in ruby [duplicate]

Answer 1

As mltsy wrote, in_groups(n, false) should do the job.

I just wanted to add a small trick to get the right balance my_array.in_group(my_array.size.quo(max_size).ceil, false).

Here is an example to illustrate that trick:

a = (0..8).to_a
a.in_groups(4, false) => [[0, 1, 2], [3, 4], [5, 6], [7, 8]]
a.in_groups(a.size.quo(4).ceil, false) => [[0, 1, 2], [3, 4, 5], [6, 7, 8]]