Swift: Testing optionals for nil

Question

I\'m using Xcode 6 Beta 4. I have this weird situation where I cannot figure out how to appropriately test for optionals.

If I have an optional xyz, is the correct w

Answer 1

Although you must still either explicitly compare an optional with nil or use optional binding to additionally extract its value (i.e. optionals are not implicitly converted into Boolean values), it's worth noting that Swift 2 has added the guard statement to help avoid the pyramid of doom when working with multiple optional values.

In other words, your options now include explicitly checking for nil:

if xyz != nil {
    // Do something with xyz
}

Optional binding:

if let xyz = xyz {
    // Do something with xyz
    // (Note that we can reuse the same variable name)
}

And guard statements:

guard let xyz = xyz else {
    // Handle failure and then exit this code block
    // e.g. by calling return, break, continue, or throw
    return
}

// Do something with xyz, which is now guaranteed to be non-nil

Note how ordinary optional binding can lead to greater indentation when there is more than one optional value:

if let abc = abc {
    if let xyz = xyz {
        // Do something with abc and xyz
    }        
}

You can avoid this nesting with guard statements:

guard let abc = abc else {
    // Handle failure and then exit this code block
    return
}

guard let xyz = xyz else {
    // Handle failure and then exit this code block
    return
}

// Do something with abc and xyz