Haskell: actual IO monad implementation, in different language?

Question

How is IO monad actually implemented?in sense of, what would be the actual implementation of the main function?

How would I call haskell function (IO) f

Answer 1

Below is the actual implementation of IO in GHC 7.10.

The IO type is essentially a state monad at type State# RealWorld (defined in GHC.Types):

{- |
A value of type @'IO' a@ is a computation which, when performed,
does some I\/O before returning a value of type @a@.
There is really only one way to \"perform\" an I\/O action: bind it to
@Main.main@ in your program.  When your program is run, the I\/O will
be performed.  It isn't possible to perform I\/O from an arbitrary
function, unless that function is itself in the 'IO' monad and called
at some point, directly or indirectly, from @Main.main@.
'IO' is a monad, so 'IO' actions can be combined using either the do-notation
or the '>>' and '>>=' operations from the 'Monad' class.
-}
newtype IO a = IO (State# RealWorld -> (# State# RealWorld, a #))

The IO monad is strict, because bindIO is defined by case matching (defined in GHC.Base):

instance  Monad IO  where
    {-# INLINE return #-}
    {-# INLINE (>>)   #-}
    {-# INLINE (>>=)  #-}
    m >> k    = m >>= \ _ -> k
    return    = returnIO
    (>>=)     = bindIO
    fail s    = failIO s

returnIO :: a -> IO a
returnIO x = IO $ \ s -> (# s, x #)

bindIO :: IO a -> (a -> IO b) -> IO b
bindIO (IO m) k = IO $ \ s -> case m s of (# new_s, a #) -> unIO (k a) new_s

This implementation is discussed in a blog post by Edward Yang.