How to define apk output directory when using gradle?
I would like to have possibility to upload apk to shared folder after each build.
This solution is work for classpath 'com.android.tools.build:gradle:3.1.2' and distributionUrl=https\://services.gradle.org/distributions/gradle-4.4-all.zip. Put the following code inside your android scope of app-level build.gradle file. When you use command ./gradlew assembleDebug or ./gradlew assembleRelease, the output folder will be copied to the distFolder.
// Change all of these based on your requirements
def archiveBuildTypes = ["release", "debug"];
def distFolder = "/Users/me/Shared Folder(Personal)/MyApplication/apk/"
def appName = "MyApplication"
applicationVariants.all { variant ->
variant.outputs.all { output ->
if (variant.buildType.name in archiveBuildTypes) {
// Update output filename
if (variant.versionName != null) {
String name = "$appName-${variant.versionName}-${output.baseName}.apk"
outputFileName = new File(name)
}
def taskSuffix = variant.name.capitalize()
def assembleTaskName = "assemble${taskSuffix}"
if (tasks.findByName(assembleTaskName)) {
def copyAPKFolderTask = tasks.create(name: "archive${taskSuffix}", type: org.gradle.api.tasks.Copy) {
description "Archive/copy APK folder to a shared folder."
def sourceFolder = "$buildDir/outputs/apk/${output.baseName.replace("-", "/")}"
def destinationFolder = "$distFolder${output.baseName.replace("-", "/")}"
print "Copying APK folder from: $sourceFolder into $destinationFolder\n"
from(sourceFolder)
into destinationFolder
eachFile { file ->
file.path = file.name // so we have a "flat" copy
}
includeEmptyDirs = false
}
tasks[assembleTaskName].finalizedBy = [copyAPKFolderTask]
}
}
}
}