Python 3: create a list of possible ip addresses from a CIDR notation

Question

I have been handed the task of creating a function in python (3.1) that will take a CIDR notation and return the list of possible ip addresses. I have looked around python.

Answer 1

Below code will generate range of IPs on providing IP and subnet. Expand the CIDR notation like(255.255.255.0)

from netaddr import *

def getFirstIp(ipAddress,subnet):
  ipBin = IPNetwork(ipAddress).ip.bits().split('.')
  subBin = IPNetwork(subnet).ip.bits().split('.')
  zipped = zip(ipBin,subBin)
  netIdList = []
  for octets in zipped:
    netIdList.append(''.join(str(b) for b in (map((lambda x: int(x[0])*int(x[1])),zip(list(octets[0]),list(octets[1]))))))
  firstIp = ''
  firstIp = '.'.join(str(int(oct,2)) for oct in netIdList)
  return firstIp


def getLastIp(ipAddress,subnet):
  ipBin = IPNetwork(ipAddress).ip.bits().split('.')
  subBin = IPNetwork(subnet).ip.bits().split('.')
  #print ipBin
  #print subBin
  revsubBin = []
  for octets in subBin:
    revB = ''.join('1' if(b == '0') else '0' for b in octets)
    revsubBin.append(revB)
  zipped = zip(ipBin,revsubBin)
  netIdList = []
  for octets in zipped:
    netIdList.append(''.join(str(b) for b in (map((lambda x: 0 if(int(x[0]) == 0 and int(x[1]) == 0) else 1),zip(list(octets[0]),list(octets[1]))))))
  #print netIdList
  lastIp = ''
  lastIp = '.'.join(str(int(oct,2)) for oct in netIdList)
  return lastIp

def getRangeOfIps(firstIp,lastIp):
  start= int(IPAddress(firstIp))
  end = int(IPAddress(lastIp))
  ipList = []
  for ip in range(start,end+1):
    ipList.append(str(IPAddress(ip)))
  return ipList

def manipulateIP():
 firstIp = getFirstIp(ipAddress,subnet)
 lastIp = getLastIp(ipAddress,subnet)
 ipList = getRangeOfIps(firstIp,lastIp)  
 print ipList