MVC 4 ViewModel not being sent back to Controller

Question

I can\'t seem to figure out how to send back the entire ViewModel to the controller to the \'Validate and Save\' function.

Here is my controller:

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Answer 1

OK, I've been working on something else and bumpend into the same issue all over again. Only this time I figured out how to make it work!

Here's the answer for anyone who might be interested:

Apparently, there is a naming convention. Pay attention:

This doesn't work:

// Controller
[HttpPost]
public ActionResult Send(BitcoinTransactionViewModel transaction)
{
}

// View
@using (Html.BeginForm("Send", "DepositDetails", FormMethod.Post, new { transaction = Model }))
{

@Html.HiddenFor(m => m.Token);
@Html.HiddenFor(m => m.Transaction.TransactionId);
.
.

This works:

// Controller
[HttpPost]
public ActionResult Send(BitcoinTransactionViewModel **RedeemTransaction**)
{
}

// View
@using (Html.BeginForm("Send", "DepositDetails", FormMethod.Post, new { **RedeemTransaction** = Model }))
{

@Html.HiddenFor(m => m.Token);
@Html.HiddenFor(m => m.Transaction.TransactionId);
.
.

In other words - a naming convention error! There was a naming ambiguity between the Model.Transaction property and my transaction form field + controller parameter. Unvelievable.

If you're experiencing the same problems make sure that your controller parameter name is unique - try renaming it to MyTestParameter or something like this...

In addition, if you want to send form values to the controller, you'll need to include them as hidden fields, and you're good to go.