Is calloc(4, 6) the same as calloc(6, 4)?

Question

I\'m a beginner C programmer, and I assumed that this would be the case, but would like some affirmation if possible.

If they are the same, why not just take one arg

Answer 1

It is the same. The reason is because most of the time you want to use a sizeof operator as one of the arguments. If passing two parameters bother you, call malloc() which has a single argument.