Scala case class private constructor but public apply method

Question

If I have the following case class with a private constructor and I can not access the apply-method in the companion object.

case class Meter private (m: Int         


        

Answer 1

It is possible with some implicit tricks:

// first case 
case class Meter[T] private (m: T)(implicit ev: T =:= Int)
object Meter { 
  def apply(m: Int) = new Meter(m + 5) 
}

created some another constructor (and apply method signature) but guaranty that parameter can be only Int.

And after you have case class with case class features (with pattern matching, hashcode & equals) exclude default constructor:

scala> val m = Meter(10)
m: Metter[Int] = Meter(15)

scala> val m = new Meter(10)
:9: error: constructor Meter in class Meter cannot be accessed in object $iw
       val m = new Meter(10)

OR with type tagging (naive implementation):

trait Private
case class Meter private (m: Integer with Private)
object Meter {
  def apply(m: Int) = new Meter((m + 5).asInstanceOf[Integer with Private])
}

It works as expected:

val x = new Meter(10)
:11: error: constructor Meter in class Meter cannot be accessed in object $iw
              new Meter(10)
              ^

val x = Meter(10)
x: Meter = Meter(15)

Some possible issues with primitive types and type tags described here