How to remove the last character from a bash grep output

Question

COMPANY_NAME=`cat file.txt | grep \"company_name\" | cut -d \'=\' -f 2` 

outputs something like this

\"Abc Inc\";

Answer 1

Using sed, if you don't know what the last character actually is:

$ grep company_name file.txt | cut -d '=' -f2 | sed 's/.$//'
"Abc Inc"