How to remove the last character from a bash grep output

Question

COMPANY_NAME=`cat file.txt | grep \"company_name\" | cut -d \'=\' -f 2` 

outputs something like this

\"Abc Inc\";

Answer 1

I'd use sed 's/;$//'. eg:

COMPANY_NAME=`cat file.txt | grep "company_name" | cut -d '=' -f 2 | sed 's/;$//'`