SQL count consecutive days

Question

This is the SQL database data:

UserTable

UserName    | UserDate      | UserCode
-------------------------------------------
user1       | 08-31-2014    | 23         


        

Answer 1

Please try:

;with T1 as(
    select 
        *, 
        ROW_NUMBER() over (  order by UserName, UserDate) ID 
    from tbl
)
,T as (
    SELECT *, 1 CNT FROM T1 where ID=1
    union all
    SELECT b.*, (case when T.UserDate+1=b.UserDate and 
                           T.UserName=b.UserName then t.CNT 
                        else T.CNT+1 end)
    from T1 b INNER JOIN T on b.ID=T.ID+1
)
select distinct UserName, MIN(UserDate), max(UserDate)
,sum(case UserCode when 0 then 0 else 1 end) From T group by UserName, CNT
having COUNT(*)>1

SQL Fiddle Demo