Tuple unpacking in for loops

Question

I stumbled across the following code:

for i,a in enumerate(attributes):
   labels.append(Label(root, text = a, justify = LEFT).grid(sticky = W))
   e = Entry         


        

Answer 1

Short answer, unpacking tuples from a list in a for loop works. enumerate() creates a tuple using the current index and the entire current item, such as (0, ('bob', 3))

I created some test code to demonstrate this:

    list = [('bob', 3), ('alice', 0), ('john', 5), ('chris', 4), ('alex', 2)]

    print("Displaying Enumerated List")
    for name, num in enumerate(list):
        print("{0}: {1}".format(name, num))

    print("Display Normal Iteration though List")
    for name, num in list:
        print("{0}: {1}".format(name, num))

The simplicity of Tuple unpacking is probably one of my favourite things about Python :D