connect by clause in regex_substr

Question

I cant get the understanding of this statement - not eveN after googling around

 
pv_no_list :=\'23,34,45,56\';
SELECT   DISTINCT REGEXP_SUBSTR (pv_no_li         


        

Answer 1

SELECT DISTINCT REGEXP_SUBSTR ('23,34,45,56','[^,]+',1,LEVEL) as "token"
FROM   DUAL
CONNECT BY REGEXP_SUBSTR ('23,34,45,56','[^,]+',1,LEVEL) IS NOT NULL
order by 1

@alfasin: Order by 1, it is throwing error for me. "missing right paranthesis" Also if I skip this then when I call the oracle procedure it gives error "ORA-22950: cannot ORDER objects without MAP or ORDER method"