C pass int array pointer as parameter into a function

Question

I want to pass the B int array pointer into func function and be able to change it from there and then view the changes in main function

#include 

        

Answer 1

Make use of *(B) instead of *B[0]. Here, *(B+i) implies B[i] and *(B) implies B[0], that is
*(B+0)=*(B)=B[0].

#include 

int func(int *B){
    *B = 5;     
    // if you want to modify ith index element in the array just do *(B+i)=
}

int main(void){

    int B[10] = {};
    printf("b[0] = %d\n\n", B[0]);
    func(B);
    printf("b[0] = %d\n\n", B[0]);
    return 0;
}