What is a difference between unsigned int and signed int in C?

Question

Consider these definitions:

int x=5;
int y=-5;
unsigned int z=5;

How are they stored in memory? Can anybody explain the bit representation

Answer 1

Assuming int is a 16 bit integer (which depends on the C implementation, most are 32 bit nowadays) the bit representation differs like the following:

 5 = 0000000000000101
-5 = 1111111111111011

if binary 1111111111111011 would be set to an unsigned int, it would be decimal 65531.